(2x^2-11x)+(3x^2+11x-4)=0

Solution for (2x^2-11x)+(3x^2+11x-4)=0 equation:

Simplifying
(2x2 + -11x) + (3x2 + 11x + -4) = 0

Reorder the terms:
(-11x + 2x2) + (3x2 + 11x + -4) = 0

Remove parenthesis around (-11x + 2x2)
-11x + 2x2 + (3x2 + 11x + -4) = 0

Reorder the terms:
-11x + 2x2 + (-4 + 11x + 3x2) = 0

Remove parenthesis around (-4 + 11x + 3x2)
-11x + 2x2 + -4 + 11x + 3x2 = 0

Reorder the terms:
-4 + -11x + 11x + 2x2 + 3x2 = 0

Combine like terms: -11x + 11x = 0
-4 + 0 + 2x2 + 3x2 = 0
-4 + 2x2 + 3x2 = 0

Combine like terms: 2x2 + 3x2 = 5x2
-4 + 5x2 = 0

Solving
-4 + 5x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 5x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 5x2 = 0 + 4
5x2 = 0 + 4

Combine like terms: 0 + 4 = 4
5x2 = 4

Divide each side by '5'.
x2 = 0.8

Simplifying
x2 = 0.8

Take the square root of each side:
x = {-0.894427191, 0.894427191}